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5n^2-137n+930=0
a = 5; b = -137; c = +930;
Δ = b2-4ac
Δ = -1372-4·5·930
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-137)-13}{2*5}=\frac{124}{10} =12+2/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-137)+13}{2*5}=\frac{150}{10} =15 $
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